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nits 1 - 3 teller has 49$10 and $20 bills in her cash drawer. The value of the bills is $870. How many $10 bills are there?

User Orr Siloni
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Final answer:

The question involving a teller's cash drawer with a mix of $10 and $20 bills can be solved by setting up a system of equations. There are 11 $10 bills in the teller's cash drawer.

Step-by-step explanation:

The question asks how many $10 bills are present in a teller's cash drawer if there are a total of 49 $10 and $20 bills with a cumulative value of $870. To solve this, we can set up a system of equations. Let x represent the number of $10 bills and y represent the number of $20 bills.

The first equation comes from the total number of bills:

x + y = 49

The second equation comes from the total value of the bills:

10x + 20y = 870

We can solve this system using substitution or elimination. If we multiply the first equation by 10 and then subtract it from the second equation, we eliminate x and can find y:

10x + 20y = 870

(10)(x + y) = (10)(49)

10x + 20y - 10x - 10y = 870 - 490

10y = 380

y = 38

Now, we substitute y back into the first equation and solve for x:

x + 38 = 49

x = 49 - 38

x = 11

Thus, there are 11 $10 bills in the teller's cash drawer.

User John Doeherskij
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