Question

Directions. Determine the following in drops per minute using the drop factor provided \( 3,000 \mathrm{~mL} \) D5W at \( 125 \mathrm{~mL} / \mathrm{hr} \) \( 15 \mathrm{gtt} / \mathrm{mL} \) Select t

Answer 1

The rate of infusion for (D5W) at
`\(125 \mathrm{~mL} / \mathrm{hr}\)`with a drop factor of
`\(15 \mathrm{gtt} / \mathrm{mL}\) is \(25 \mathrm{gtt/min}\).`

Step-by-step explanation:

To determine the drops per minute
`(\(gtt/min\)),` you can use the formula:

`\[\text{{Drops per minute}} = \left( \frac{{\text{{Volume per hour}}}}{{\text{{Drop factor}}}} \right) * (1)/(60)\]`

In this case, the volume per hour is
`\(125 \mathrm{~mL/hr}\)`and the drop factor is
`\(15 \mathrm{gtt/mL}\)`. Plug these values into the formula:

`\[\text{{Drops per minute}} = \left( \frac{{125}}{{15}} \right) * (1)/(60)\]`

Now, calculate the drops per minute:

`\[\text{{Drops per minute}} = \left( \frac{{25}}{{3}} \right) * (1)/(60) = (25)/(180) * (1)/(60) = (25)/(10,800)\]`

Simplify the fraction:

`\[\text{{Drops per minute}} = (5)/(2,160)\]`

To express this in a more practical form, convert this fraction to a decimal:

`\[\text{{Drops per minute}} \approx 0.00231\]`

Finally, convert the decimal to a whole number by multiplying by 60:

`\[\text{{Drops per minute}} \approx 0.00231 * 60 \approx 0.1386 \approx 0.14\]`

Therefore, the drops per minute is approximately (0.14) or
`\(25 \mathrm{gtt/min}\).`