Final answer:
The given series diverges.
Step-by-step explanation:
In order to determine whether the series ∑n=3∞ 1⁄√(n-2) converges or diverges, we can use the comparison test.
We can compare this series to the harmonic series, ∑n=1∞ 1/n, which is a well-known divergent series.
By comparing the terms of the given series to the terms of the harmonic series, we can see that for all n ≥ 3, ¹⁄√(n-2) ≥ 1/n. Since the harmonic series diverges, the given series also diverges.