411,020 views
38 votes
38 votes
Select each exact root. If the exact roots cannot be found, select the consecutive integers between which the roots are located. If there are no roots, select no real solution.

x2+6x+6=0

Multiple select question.

A) no real solution

B) between −2 and −1

C) between −5 and −4

D) −5

E) −1

F) between 4 and 5

G) between 1 and 2

User AndreVitorio
by
3.1k points

1 Answer

11 votes
11 votes

Answer:

C, B

Explanation:


x^2+6x+6=0 \\ \\ x=(-6 \pm √(6^2-4(6)))/(2(1)) \\ \\ x=-3 \pm √(3) \\ \\ √(3) \approx 1.7 \implies -5<-3-√(3)<-4, -2<-3+√(3)<-1

User Pille
by
3.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.