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Mar 08, 8:20:07 PM Solve the equation x^(2)-24x+70=-8x+27 to the nearest tenth.

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Final answer:

The solutions to the equation rounded to the nearest tenth are approximately x = 8 + √21 and x = 8 - √21.

Step-by-step explanation:

To solve the equation x2-24x+70=-8x+27, we can start by rearranging it:

x2-24x+8x+70-27=0

x2-16x+43=0

Now we can use the quadratic formula, which is x = (-b ± √(b²-4ac))/(2a). In this equation, a = 1, b = -16, and c = 43. Substituting these values, we get:

x = (-(-16) ± √((-16)²-4(1)(43)))/(2(1))

x = (16 ± √(256-172))/2

x = (16 ± √84)/2

x = (16 ± 2√21)/2

x = 8 ± √21

Therefore, the solutions to the equation rounded to the nearest tenth are approximately x = 8 + √21 and x = 8 - √21.

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