171k views
5 votes
Mar 21, 11:50:01AM Solve the equation x^(2)+13x+24=0 to the nearest tenth.

User Everon
by
7.8k points

1 Answer

3 votes

Final answer:

To solve the equation x² + 13x + 24 = 0 to the nearest tenth, we can use the quadratic formula. The solutions are approximately -2.2 and -10.3.

Step-by-step explanation:

To solve the equation x² + 13x + 24 = 0 to the nearest tenth, we can use the quadratic formula. For an equation of the form ax² + bx + c = 0, the solutions are given by:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values from the equation we have:

x = (-13 ± √(13² - 4(1)(24))) / (2)

Simplifying further, we get:

x ≈ (-13 ± √(169 - 96)) / 2

x ≈ (-13 ± √73) / 2

Using a calculator to find the square root of 73, we have:

x ≈ (-13 ± 8.54) / 2

We can simplify this further by evaluating the two possible solutions:

x₁ ≈ (-13 + 8.54) / 2 ≈ -2.23

x₂ ≈ (-13 - 8.54) / 2 ≈ -10.27

Therefore, the solutions to the equation x² + 13x + 24 = 0 to the nearest tenth are approximately -2.2 and -10.3.

User Jay Kumar
by
8.4k points