Final answer:
The equilibrium constant for the given net ionic equation is K = [H₃O⁺][OH⁻], and the ion-product for water is represented as Kw with a value of 1.0 × 10⁻¹⁴ at 25°C.
Step-by-step explanation:
The equilibrium constant for the net ionic equation H₃O⁺(aq) + OH⁻(aq) <-> 2 H₂O(l) can be calculated using the concentration of H₃O⁺(aq) and OH⁻(aq) ions. The equilibrium constant, represented as K, is only dependent on the concentrations of the ions involved in the reaction and does not include the concentration of H₂O(l) as it is a pure liquid.
Thus, the equilibrium constant expression is K = [H₃O⁺][OH⁻]. The equilibrium constant for the self-ionization of water is also called the ion-product for water, represented as Kw, with a value of 1.0 × 10⁻¹⁴ at 25°C.
In summary, the equilibrium constant for the given net ionic equation is K = [H₃O⁺][OH⁻], and the ion-product for water is represented as Kw with a value of 1.0 × 10⁻¹⁴ at 25°C.