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Calculate the cente of the circle whose equation is : x^(2)+y^(2)-4x+6y-17=0

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Final answer:

To find the center of the circle, we need to rearrange the equation into the standard form (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle and r is the radius.

Step-by-step explanation:

The equation of the circle is given by:

x2 + y2 - 4x + 6y - 17 = 0

To find the center of the circle, we need to rearrange the equation into the standard form (x - h)2 + (y - k)2 = r2, where (h, k) represents the center of the circle and r is the radius.

By completing the square on the x and y terms, we get:

(x - 2)2 + (y + 3)2 = 32

Thus, the center of the circle is (2, -3) and the radius is √32.

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