In Δ JLP, m ∠ JMP = 3x - 6, JK = 3y - 2, and LK = 5y - 8 then the value of x = 32.
A line that crosses a triangle's vertex, or corner, and its opposite side at a right angle, or 90 degrees, is referred to as an altitude in geometry.
The other side is known as the base. Triangles share three opposed sides and three vertices.
The perpendicular drawn from a triangle's vertex to its opposite side is known as its height.
Together with the base, the altitude—also referred to as the triangle's height—forms a right-angle triangle.
Since JM is at an altitude of ΔJLP, m ∠ JMP = 90
3x - 6 = 90
simplifying the above equation we get
3x = 96
Dividing both sides of the equation by 3, we get
x = 32
The value of x = 32.
Question
In ΔJ L P, m ∠ J M P=3 x-6 J K=3 y-2 , and L K=5 y-8 .
If JM is an altitude of Δ J L P , find x .