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A 60n is rested on a rough inclined plane. the static friction between the block and the plane is

User Sudharshan
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The maximum angle of inclination before the 60 N block begins to slide due to static friction can be determined using the formula tan(θ)= static friction force/normal force.

The maximum angle of inclination before the 60 N block begins to slide due to static friction is determined by the balance between the force component parallel to the incline and the static friction force opposing it. The key relationship is expressed through the equation tan(θ)= static friction force/normal force. As the angle of inclination increases, the component of the weight parallel to the incline also increases. At the maximum angle, the force parallel to the incline equals the maximum static friction force, preventing the block from sliding. This equilibrium condition establishes the critical angle beyond which the static friction force is exceeded, leading to the initiation of sliding motion. The tan(θ) expression encapsulates this balance, providing a quantitative measure of the maximum angle of inclination for the given block resting on the rough inclined plane.

Complete ques:

What is the maximum angle of inclination for the rough inclined plane before the 60 N block begins to slide due to static friction?

User Mondy
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