Question

home smoke alarms are able to detect CO quantities as low as 0.01 qtr. how many grams of CO are in a 40000L room at 25 celsius if the CO pressure is o.o1 atm?

Answer 1

To determine the grams of CO in a 40000L room, we use the Ideal Gas Law PV=nRT with conversions for temperature to Kelvin. Solving for n and multiplying by molar mass gives us approximately 45.48 grams of CO.

Step-by-step explanation:

To calculate the number of grams of CO in a 40000L room at 0.01 atm and 25 degrees Celsius, we can use the Ideal Gas Law, which is PV = nRT. In this equation, P represents the pressure, V represents the volume, n is the number of moles, R is the universal gas constant (0.0821 L atm / (mol K)), and T is the temperature in Kelvin.

First, we need to convert the temperature to Kelvin:

• T (K) = 25 (C) + 273.15 = 298.15 K

Now we can use the Ideal Gas Law to find n:

• PV = nRT
• (0.01 atm) * (40000 L) = n * (0.0821 L atm / (mol K)) * (298.15 K)
• n = (0.01 atm * 40000 L) / (0.0821 L atm / (mol K) * 298.15 K)
• n ≈ 1.624 mol of CO

To convert moles to grams, we use the molar mass of CO, which is approximately 28.01 g/mol:

• Mass of CO = n * molar mass
• Mass of CO ≈ 1.624 mol * 28.01 g/mol
• Mass of CO ≈ 45.48 g

Therefore, there would be approximately 45.48 grams of CO in a 40000L room at 25 degrees Celsius with a CO pressure of 0.01 atm.