Question

Give the value of h and k of the given equation y^(1)=(x+4)^(2)-5

Answer 1

To find the values of h and k in the given equation y^2 = (x+4)^2-5, we can match it with the standard equation for a parabola, (x-h)^2 = 4a(y-k), and find that h = -4 and k = -5.

Step-by-step explanation:

To find the values of h and k in the equation y^2 = (x+4)^2-5, we need to match the given equation with the standard equation for a parabola, which is (x-h)^2 = 4a(y-k). Comparing the equations, we can see that h = -4 and k = -5.