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In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to ________. In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to ________. 8.314 m3-Pa/mol-K 0.08206 atm L mol-1K-1 1.987 cal mol-1K-1 62.36 L torr mol-1K-1 none of the above

User Ranjana
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Answer:


8.314\ \text{m}^3\text{Pa/mol K}

Step-by-step explanation:

Let us find the unit of the gas constant R from the ideal gas equation. We substitute the units of the quantities rearrange them and get the units of the gas constant.

P = Pressure = Pa

V = Volume =
\text{m}^3

n = Moles = mol

T = Temperature = K


PV=nRT\\\Rightarrow R=(PV)/(nT)\\\Rightarrow R=\frac{\text{Pa m}^3}{\text{mol K}}

Here,
\text{Pa} is used so the gas constant value that must be used is
8.314\ \text{m}^3\text{Pa/mol K}.

User Incleaf
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