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If f(x)=x^(3)+5x^(2)+7x-13+x-1is a fac tor of f(x)then find all the 0s of f(x)algebraically

User Egurb
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Final answer:

To find the zeros of the given function f(x), we use polynomial long division or synthetic division to find the other factor. The zeros of the function are x = -4 and x = 2.

Step-by-step explanation:

To find the zeros of the function f(x), we need to solve the equation f(x) = 0. Given that f(x) = x^3 + 5x^2 + 7x - 13x - 1 is a factor of f(x), we can use polynomial long division or synthetic division to find the other factor.

Performing synthetic division, we divide f(x) by x - 1:

1│ 1 5 7 -13 -1
────── -4 1 8 -5
1 1 8 -5 | 3

The quotient is x^2 + x + 8 - 5/(x - 1) = x^2 + x + 8 - 5/(x - 1). Setting this quotient equal to zero and solving for x, we get:

x^2 + x + 8 - 5/(x - 1) = 0.

By factoring the quadratic equation, we find the zeros of the function to be:

x^2 + x + 8 - 5/(x - 1) = 0
(x + 4)(x - 2) = 0
x = -4 or x = 2
User Bao Le
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