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What is the distance between (5,7) and (11,-1)

1 Answer

5 votes

Answer:

10 units

Explanation:

To find the distance between two points on a graph, we use the distance formula
d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2 where
d is the distance between points
(x_1,y_1) and
(x_2,y_2).

For this problem, we will identify
(x_1,y_1)\rightarrow(5,7) and
(x_2,y_2)\rightarrow(11,-1):


d=√((y_2-y_1)^2+(x_2-x_1)^2)\\\\d=√((-1-7)^2+(11-5)^2)\\\\d=√((-8)^2+(6)^2)\\\\d=√(64+36)\\\\d=√(100)\\\\d=10

Therefore, the distance between
(5,7) and
(11,-1) is 10 units

User Joe Casadonte
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