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Mar 12, 2:57:12 PM Solve the system of equations using elimination: -2x-y=13 and 7x+3y=-42

1 Answer

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Final answer:

The solution to the system of equations is x = -3 and y = -7. This is found by first using the elimination method to find the value of x and then substituting the found value of x into one of the original equations to find the value of y.

Step-by-step explanation:

To solve the system of equations using elimination, we have the following two equations:

-2x - y = 13

7x + 3y = -42

We need to eliminate one variable. Let's eliminate y. To do this, we can multiply the first equation by 3 to make the coefficients of y equal but opposite in sign:

-2x * 3 -> -6x

-y * 3 -> -3y

13 * 3 -> 39

Now our equations are:

-6x - 3y = 39

7x + 3y = -42

Adding these two equations together:

-6x + 7x = x

-3y + 3y = 0

39 + (-42) = -3

So, x = -3.

Now, substitute x = -3 into the first original equation:

-2(-3) - y = 13

6 - y = 13

Subtract 6 from both sides:

-y = 13 - 6

-y = 7

Divide both sides by -1:

y = -7

The solution to the system of equations is x = -3 and y = -7.

User James Holland
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