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A drug is ordered to be administed iv at the rate of 4 mU/min,and may increase by 2 Mu/min q 15min to a max of 10 mU/min. The iv streanght is 5 mu/Ml. constuct the first two lines of the titration talbe for this order

A. 0.8 mL/min and 2.8 mL/min
B. 4 mL/min and 6 mL/min
C. 4 mL/min and 6 mL/min
D. 0.8 mL/min and 6 mL/min

1 Answer

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Final answer:

To construct the titration table for this IV drug order, the initial infusion rate is calculated at 0.8 mL/min, and the rate after the first increase (15 minutes later) is 1.2 mL/min.

Step-by-step explanation:

The question involves constructing the first two lines of a titration table for an IV drug order. The drug should be administered at a rate of 4 mU/min, and it can increase by 2 mU/min every 15 minutes to a maximum of 10 mU/min. The IV strength is 5 mU/ml. We need to calculate the initial infusion rate in mL/min as well as the infusion rate after the first increase.

The initial rate is 4 mU/min, and since 1 mL contains 5 mU, the initial rate in mL/min is 4 mU/min / 5 mU/mL = 0.8 mL/min. After 15 minutes, the rate increases by 2 mU/min to a total of 6 mU/min. Thus, the new rate in mL/min is 6 mU/min / 5 mU/mL = 1.2 mL/min.

Therefore, the first two lines of the titration table would be:

  • Initial Rate: 0.8 mL/min
  • Rate After 15 Minutes: 1.2 mL/min
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