To find the equation of a line passing through two points, we can use the point-slope form of a linear equation. The equation of the line passing through (-4, -2) and (3, 6) is 8x-7y=18.
To find the equation of a line passing through two points, we can use the point-slope form of a linear equation.
Let's use the points (-4, -2) and (3, 6) to find the equation.
Step 1: Find the slope (m) using the formula: m = (y2 - y1) / (x2 - x1) = (6 - (-2)) / (3 - (-4)) = 8/7.
Step 2: Use the slope and one of the given points in the point-slope form: y - y1 = m(x - x1).
Using the point (-4, -2): y - (-2) = (8/7)(x -(-4)).
Simplifying this equation gives us the slope-intercept form: 8x - 7y - 16 = 0.
To convert to the required form, multiply the equation by -7: -56x + 49y + 112 = 0.
Therefore, the equation of the line is 8x-7y=18.
The probable question may be:
7. Find the equation of the line passing through the points (-4, -2) and (3,6),
give the equation in the form ax + by + c = 0,
where a, b, c are whole numbers and a > 0.