235k views
3 votes
How to do i solve this?

How to do i solve this?-example-1

1 Answer

2 votes

To find the equation of a line passing through two points, we can use the point-slope form of a linear equation. The equation of the line passing through (-4, -2) and (3, 6) is 8x-7y=18.

To find the equation of a line passing through two points, we can use the point-slope form of a linear equation.

Let's use the points (-4, -2) and (3, 6) to find the equation.

Step 1: Find the slope (m) using the formula: m = (y2 - y1) / (x2 - x1) = (6 - (-2)) / (3 - (-4)) = 8/7.

Step 2: Use the slope and one of the given points in the point-slope form: y - y1 = m(x - x1).

Using the point (-4, -2): y - (-2) = (8/7)(x -(-4)).

Simplifying this equation gives us the slope-intercept form: 8x - 7y - 16 = 0.

To convert to the required form, multiply the equation by -7: -56x + 49y + 112 = 0.

Therefore, the equation of the line is 8x-7y=18.

The probable question may be:

7. Find the equation of the line passing through the points (-4, -2) and (3,6),

give the equation in the form ax + by + c = 0,

where a, b, c are whole numbers and a > 0.

User Sylvix
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories