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Consider the differential equation (1 + ye^0)dx + (2y + xe^(xy))dy = 0. Then the DE is.?

User Rujikin
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Final answer:

The given differential equation is a nonlinear differential equation.

Step-by-step explanation:

The given differential equation is (1 + ye^0)dx + (2y + xe^(xy))dy = 0.

To determine the type of this differential equation, we can look at the coefficients of dx and dy. If the coefficients are functions of x and/or y, then it is a nonlinear differential equation. In this case, both coefficients are functions of x and y, so the given differential equation is a nonlinear differential equation.

User Alessandro Annini
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