Final answer:
To find the polynomial with a leading coefficient of 5 and roots (1/5) and 2+-3i, we can use the fact that complex roots always come in conjugate pairs.
Step-by-step explanation:
To find the polynomial with a leading coefficient of 5 and roots (1/5) and 2+-3i, we can use the fact that complex roots always come in conjugate pairs. So the other complex root will be 2-3i.
To get the polynomial, we start with the expression (x - (1/5))(x - (2 + 3i))(x - (2 - 3i)). Multiplying this out, we get:
5x³ - 15x² + 17x - 5 = 0