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The sum of the digits of a certain two-digit number is 7. Reversing its digits increases the number by 9. What is the number?​

User Jbx
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1 Answer

3 votes

Answer:

The original two-digit number is 34.

Explanation:

Let's represent the original two-digit number as "xy", where "x" is the tens digit and "y" is the ones digit.

We have the following equation:

x + y = 7 ---(Equation 1)

The second equation states that reversing the digits increases the number by 9. This can be expressed as:

10y + x = 10x + y + 9 ---(Equation 2)

Now, we can solve this system of equations to find the values of "x" and "y".

Multiplying Equation 1 by 10, we get:

10x + 10y = 70

Subtracting Equation 1 from Equation 2, we have:

10y + x - (10x + y) = 9

Simplifying:

9y - 9x = 9

Now, let's divide both sides of the equation by 9:

y - x = 1 ---(Equation 3)

Next, let's add Equation 1 and Equation 3:

x + y + y - x = 7 + 1

Simplifying:

2y = 8

Dividing both sides by 2:

y = 4

Substituting the value of "y" back into Equation 1:

x + 4 = 7

Subtracting 4 from both sides:

x = 3

= 34

User Thomas Taylor
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