Final answer:
The nuclear reaction 126/50Sn → 126/51Sb + 1/0n can be represented as follows: 126/50Sn → 126/51Sb + 1/0n. In this reaction, a beta particle (1/0n) is emitted from a tin-126 nucleus, resulting in the formation of an antimony-126 nucleus. The daughter isotope in this reaction is antimony-126 (126/51Sb).
Step-by-step explanation:
The nuclear reaction 126/50Sn → 126/51Sb + 1/0n can be represented as follows:
126/50Sn → 126/51Sb + 1/0n
In this reaction, a beta particle (1/0n) is emitted from a tin-126 nucleus, resulting in the formation of an antimony-126 nucleus. The daughter isotope in this reaction is antimony-126 (126/51Sb).