Final answer:
The charge of a Vanadium ion in the compound V2O5 is +5, as it must balance the -10 total charge contributed by the oxygen atoms in the compound.
Step-by-step explanation:
The charge of a Vanadium ion in the compound V2O5 can be determined by looking at the overall charge balance within the compound. In V2O5, each oxygen atom has a -2 charge, giving a total of 5 oxygen atoms × -2 = -10 total charge from oxygen. Since the compound is neutral, the two vanadium ions must balance this with a total charge of +10. Therefore, each Vanadium ion has a charge of +5 to balance the -10 from the oxygen atoms.
The charge of a Vanadium ion in V2O5 is +5.