Final answer:
The cross between white-eyed females (XrXr) and red-eyed males (XRY) yields heterozygous red-eyed females (XrX) and white-eyed males (XrY).
Step-by-step explanation:
The question pertains to the outcome of a genetic cross involving X-linked traits in Drosophila, more commonly known as fruit flies. The specific cross is between white-eyed females (genotype XrXr) and red-eyed males (genotype XRY). Using the provided information, we can construct a Punnett square to determine the genotypes and phenotypes of the offspring.
Here's how the Punnett square would look:
- Xr from the female and X from the male gives XrX - Red-eyed female (heterozygous)
- Xr from the female and Y from the male gives XrY - White-eyed male
Since the females have two X chromosomes, they will always receive the recessive white-eyed allele from the mother and the dominant red-eyed allele from the father, resulting in heterozygous red-eyed females. The males, having only one X chromosome, will receive the white-eyed allele from their mother and the Y chromosome from their father, resulting in white-eyed males.
Thus, the types of offspring produced are heterozygous red-eyed females (XrX) and white-eyed males (XrY).