Final answer:
The zeros of the equation are approximately x = -6.94 and x = 2.94.
Step-by-step explanation:
This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = 4, and c = -16. To find the zeros of the equation, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
Substituting the values from our equation, we get:
x = (-4 ± √(4² - 4(1)(-16))) / (2(1))
Simplifying further, we have:
x = (-4 ± √(16 + 64)) / 2
x = (-4 ± √(80)) / 2
x = (-4 ± 8.94) / 2
Therefore, the zeros of the equation are approximately x = -6.94 and x = 2.94.