Question

Find the zeros
X^4+4x^3+4x^2-16

Answer 1

The zeros of the equation are approximately x = -6.94 and x = 2.94.

Step-by-step explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = 4, and c = -16. To find the zeros of the equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values from our equation, we get:

x = (-4 ± √(4² - 4(1)(-16))) / (2(1))

Simplifying further, we have:

x = (-4 ± √(16 + 64)) / 2

x = (-4 ± √(80)) / 2

x = (-4 ± 8.94) / 2

Therefore, the zeros of the equation are approximately x = -6.94 and x = 2.94.