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A beaker is divided by a membrane that is permeable to water and glucose, but not to sucrose. Equal volumes of solutions are added to side A and B with the initial concentrations as shown below. Initially, the liquid levels on both sides are the same.

User Trin
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Final answer:

The question pertains to the biological process of osmosis, where water moves across a membrane from an area of higher water concentration to one of lower water concentration until isotonic conditions are achieved. This concept applies to solutions with different solutes, such as glucose, and is critical in biological systems like cells, where the cell membrane regulates osmosis.

Step-by-step explanation:

The scenario described involves a beaker divided into two compartments by a semipermeable membrane that allows the passage of water and glucose but not sucrose. This setup demonstrates the biological process of osmosis, which pertains to the movement of water across a semipermeable membrane from an area of higher water concentration to an area of lower water concentration until equilibrium is reached. The side with the hypotonic solution, which has a higher water concentration, will have water molecules moving through the membrane to the side with the hypertonic solution with a lower water concentration. This process continues until the concentration of water and the concentrations of permeable substances are equal on both sides, termed isotonic.

This principle can also be observed with glucose solutions of different concentrations, demonstrating that the water's vapor pressure is affected by the dissolved solutes and that water will transfer from a beaker containing pure water to one containing a glucose solution due to differences in the vapor pressure. In the context of cells, this is also relevant as the cell membrane acts similarly to the semipermeable membrane in the beaker, controlling the movement of substances and maintaining osmotic balance.

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