Question

WHAT IS THE ANSWER PLEASE HELP ME

Answer 1

⇒Note I am going to solve them step by step for you to understand.

1.

`3(x)+3(5)=3x+5\\3x+15=3x+5\\3x-3x=5-15\\no\\solution`

since 0≠-10

2.

`-3(x)-3(-5)=-3x-15\\-3x+15=-3x-15\\-3x+3x=-15-15\\0\\eq -30\\no\\solution`

3.

`3(-x)+3(5)=8-x\\-3x+15=8-x\\\\-3x+x=8-15\\-2x=-7\\(-2x)/(-2) =(-7)/(-2) \\x=(7)/(2)`

4.

`-3(-x)-3(-5)=3x+15\\3x+15=3x+15\\3x-3x=15-15\\0=0\\`

Note there is no certain value for x as any value you insert as x can make the whole equation true.

No solution is the answer for Q4

Answer 2

option 4

Explanation:

Use distributive property: a(b +c) = (a*b) + (a*c).

Multiply each term of (-x - 5) by (-3).

-3( -x - 5) = ( -3* -x) + (-3*-5)

= ( 3x ) + ( 15)

= 3x + 15