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The elemental iron content of ferrous fumarate is 33%. For a

patient to receive 100 mg of elemental iron how many mg of ferrous
fumarate would be required?

1 Answer

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Final answer:

To calculate the amount of ferrous fumarate needed for 100 mg of elemental iron, with ferrous fumarate having 33% iron content, you divide 100 mg by 0.33, resulting in approximately 303 mg of ferrous fumarate.

Step-by-step explanation:

To find out how many milligrams of ferrous fumarate are required to provide 100 mg of elemental iron, where ferrous fumarate contains 33% elemental iron, we need to use a simple proportion.

First, express the percentage as a decimal, which is 0.33 for 33%. Then set up the equation using the proportion of elemental iron to ferrous fumarate:

Elemental Iron (mg) = Ferrous Fumarate (mg) × Elemental Iron Percentage

100 mg = Ferrous Fumarate (mg) × 0.33

To solve for the quantity of ferrous fumarate needed, divide the amount of elemental iron required by the decimal equivalent of the percentage:

Ferrous Fumarate (mg) = 100 mg / 0.33

When you perform the division, you get approximately 303.03 mg of ferrous fumarate.

Therefore, to obtain 100 mg of elemental iron, approximately 303 mg of ferrous fumarate would be required.

User Michal Hatak
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