Answer:A = A0ekt
where A0 = 3000, k = 7% (or 0.07)
A = (3000 + 630) = 3630 = 3000e[(0.07)t]
Our goal is to find t
[(3630)/(3000)] = e[(0.07)t]
ln{[(3630)/(3000)]} = (0.07)t
(0.07)t = 2*ln(11/10)
t = = 2.7 days
Explanation:
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