Question

Three bag of sweet weight 6 3/4 kg two of them have the same weight and the third bag is heavier than each of the bag of equal weight by 1 1/5 find weight of each bag

Answer 1

lighter bag weighs 1
`(83)/(100)`

heavier bag weighs 3
`(3)/(100)`

Explanation:

let x = weight of lighter bag

let x+6/5 = weight of heavier bag

2x + x+6/5 = 6 3/4

3x + 6/5 = 27/4

3x = 27/4 - 6/5

3x = 111/20

x = 111/20 ÷ 3

x = 1 83/100

x+ 6/5 = 3 3/100

Answer 2

Answer: the weight of each bags are 1.85kg,
1.85kg and 3.05 kg
Explanation:
Total weight of the three bags is
6 3/4 kg. Converting to decimal, it becomes 6.75
kg.
Two of them have the same weight. Let X
represent the bags of equal weight. Their total
weight would be 2x. The third bag is heavier
than each of the bags of equal weight by 1 1/5
kg. Converting to decimal, it becomes 1.2kg. It
means that the weight of the third bag would be
x + 1.2
Therefore, for the three bags,
2x + × + 1.2 = 6.75
3x = 6.75 - 1.2 = 5.55
x=5.55/3=1.85
Weight of the third bag is
1.85+1.2=3.05kg