Final answer:
A RrYy plant can produce four types of gametes: RY, Ry, rY, and ry. When crossing RrYY and rrYy pea plants in a Punnett square, you would need 16 squares for the analysis. AaBb can produce gametes of types AB, Ab, aB, and ab. The correct option is D. RY, Ry, rY, or ry
Step-by-step explanation:
The gametes that can be produced by a plant with the genotype RrYy are RY, Ry, rY, and ry. This is due to the law of independent assortment, which states that each allele for the seed shape gene (either R or r) is equally likely to be combined with each allele for the seed color gene (either Y or y) in the gametes.
A cross between RrYY and rrYy pea plants can produce the following possible genotypes: RrYy, rrYy, RrYY, and rrYY, which will result in phenotypic ratios of round-yellow peas and round-green peas. To perform a Punnett square analysis of this cross, you would need 4 squares for each possible gamete match, resulting in a total of 16 squares.
When considering the types of gametes an individual with the genotype AaBb can produce, the correct answer is AB, Ab, aB, ab, which reflects the possible combinations of the alleles from each gene.The correct option is D. RY, Ry, rY, or ry