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Select the correct answer from each drop-down menu. A ball starts from rest. It rolls down a ramp and reaches the ground after 4 seconds. Its final velocity when it reaches the ground is 7.0 meters/second. The initial velocity of the ball is meters/second, and its acceleration is meters/second2.

User Super Cool
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2 Answers

3 votes

Final answer:

The question involves calculating the initial velocity and acceleration of a ball rolling off a ramp, with the use of kinematic equations. The ball's initial velocity is 0 meters/second and the acceleration is found to be 1.75 meters/second².

Step-by-step explanation:

The question relates to a ball rolling off a ramp, where its initial velocity, final velocity, and acceleration need to be determined. Given that a ball starts from rest and reaches a final velocity of 7.0 meters/second after 4 seconds, we can use the following kinematic equation to solve for acceleration:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the ball starts from rest, u = 0 m/s. Plugging in the numbers, we get 7.0 m/s = (0 m/s) + a(4 s), which leads to an acceleration () of 1.75 m/s².

The initial velocity of the ball is 0 meters/second, and its acceleration is 1.75 meters/second².

User Radek Pech
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2 votes

Answer: 0 and 1.75

Step-by-step explanation:

User Ross Gurbutt
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