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How much total heat is required to heat 50 g of ice from its temperature of -500 C to its boiling point? Use the values below and show each step of the calculations for full credit.

How much total heat is required to heat 50 g of ice from its temperature of -500 C-example-1

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The total heat required is 42725 J.

To calculate the total heat required, first calculate the heat to raise the temperature of ice from -50°C to 0°C (q1), the heat for phase change from ice to water at 0°C (q2), and the heat to raise the temperature of water from 0°C to its boiling point (q3). Then, sum these values: Q = q1 + q2 + q3. Using the formula Q = m * c * ΔT, where m is mass, c is specific heat, and ΔT is temperature change.

q1​=m⋅c ice​⋅ΔT1

q2=m⋅Enthalpy of Fusion

q3=m⋅cwater ⋅ΔT2

Q=q1​+q2​+q3

Substitute the given values:

q1​=50g⋅2.05J/g-°C⋅(0−(−50))°C

q2​=50g⋅334J/g

q3​=50g⋅4.18J/g-°C⋅(100−0)°C

Q=q1​+q2​+q3

Substitute the given values:

Q=(50⋅2.05⋅50)+(50⋅334)+(50⋅4.18⋅100)

Q=5125+16700+20900

Q=42725Joules

Therefore, the total heat required is 42725 J.

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