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What is the equation for the parabola graphed below

What is the equation for the parabola graphed below-example-1
User Mopsled
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1 Answer

17 votes
17 votes

Answer:


y = x^2 - 2x -1

Explanation:

General Form of a parabola :


y = a (x - h)^2 + k

Solving :

h and k refer to the point of the vertex. In this case, it's (1, -2), so :


y = a(x - 1)^2 - 2

Plug in values for x and y. In this case, they're (0, -1), so :


-1 = a(0 - 1)^2 - 2\\-1 =a(1) - 2\\1 = a

Plug in all values :


y = ( x - 1)^2 -2

Further simplifying :


y = ( x - 1 )^2 - 2 \\y = (x^2-2x + 1) - 2\\y = x^2 - 2x -1

User Ishwardgret
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