Question

What is the perimeter of a rectangle with a length of 40 feet

and a width of 12 feet?
Perimeter
Square
Rectangle
OA) 32 feet
OB) 64 feet
OC) 104 feet
OD) 480 feet
P=4s
P = 21+ 2w or P = 2(/+w)

Answer 1

The perimeter of a rectangle with a length of 40 feet and a width of 12 feet is calculated using the formula P = 2l + 2w, resulting in a perimeter of 104 feet.

Step-by-step explanation:

The perimeter of a rectangle is calculated by adding together two times the length and two times the width. The formula for the perimeter (P) of a rectangle is P = 2l + 2w, where l is the length and w is the width of the rectangle.

For a rectangle with a length of 40 feet and a width of 12 feet:

• Double the length: 2 × 40 feet = 80 feet
• Double the width: 2 × 12 feet = 24 feet
• Add them together: 80 feet + 24 feet = 104 feet

Therefore, the perimeter of this rectangle is 104 feet.