Question

A bullet is fired straight up from a gun with a

muzzle velocity of 130 m/s.
Neglecting air resistance, what will be its
displacement after 3.6 s? The acceleration of
gravity is 9.8 m/s
2
.
Answer in units of m

Answer 1

The bullet's displacement after 3.6 seconds is approximately -510.24 meters.

To find the displacement of the bullet after 3.6 seconds, we can use the kinematic equation:

displacement = initial velocity * time + 0.5 * acceleration * time^2

Since the bullet is fired straight up, the initial velocity is 130 m/s and the acceleration is -9.8 m/s^2 (negative because it is acting in the opposite direction of motion). Plugging in the values, we have:

displacement = 130 m/s * 3.6 s + 0.5 * -9.8 m/s^2 * (3.6 s)^2

After solving for displacement, we find that the bullet's displacement after 3.6 seconds is approximately -510.24 meters.