Question

If the heat of fusion for water is 334 J/g, how many joules are needed to melt 45.0 g of ice at 0.0 °C?

Answer 1

To melt 45.0 g of ice at 0.0 °C, you would need 15030 Joules of heat.

Step-by-step explanation:

To calculate the amount of heat needed to melt 45.0 g of ice at 0.0 °C, we can use the formula Q = mLf, where Q is the amount of heat, m is the mass of the ice, and Lf is the heat of fusion of water. In this case, the heat of fusion of water is given as 334 J/g.

So, the amount of heat needed can be calculated as:

Q = (45.0 g)(334 J/g) = 15030 J.

Therefore, 15030 Joules are needed to melt 45.0 g of ice at 0.0 °C.