Answer:
the power generation potential is 2.705 x 10⁶ J/s.
Step-by-step explanation:
Given;
height below the free surface of a large water reservoir, h = 120 m
mass flow rate of the water, m' = 2300 kg/s
The power generation potential is calculated as;

Therefore, the power generation potential is 2.705 x 10⁶ J/s.