Question

A 9.25 kg bowling ball is hung on a 9.5 m long rope. It is then pulled back until the rope makes an angle of 35° with the vertical and released. Find the tension in the rope when the ball is at the lowest point. Give your answer in N and with 3 significant figures.

Answer 1

123.6 N

Step-by-step explanation:

I will try to answer this

Find height of the ball

9. 5 - 9.5 cos 35 = 1.72 m of potential energy

PE = mgh will be converted to KE at the bottom of the swing

mgh = 1/2 m v^2

sqrt( 2 gh ) = v at the bottom = 5.81 m/s

then the tension is the mass times the acceleration of gravity PLUS the acceleration of circular motion v^2 / r

F = ma

F = 9.25 kg ( 9.81 m/s^2 + 5.81^2 / 9.5 m/s^2 ) = tension = 123.6 N

(Let me know if this is incorrect, and I will research a bit more)