Final answer:
The oxidation state of phosphorus in H3PO2 is +1, which is calculated by assigning known oxidation states to hydrogen (+1) and oxygen (-2) and solving for the phosphorus oxidation state.
Step-by-step explanation:
To determine the oxidation state of phosphorus in H3PO2, we apply the rules for assigning oxidation numbers. Hydrogen, by guideline 3, is assigned an oxidation state of +1 in most of its compounds, and oxygen is assigned an oxidation state of -2. Using these values, we can set up an equation based on the fact that the sum of oxidation states in a neutral compound is zero:
- (3 × H) + (1 × P) + (2 × O) = 0;
- (3 × +1) + P + (2 × -2) = 0;
- 3 + P - 4 = 0;
- P = +1.
Therefore, the oxidation state of phosphorus in H3PO2 is +1.