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What is the volume of 64g of oxygen gas at a pressure of 600 torr and a temperature of 12 degrees C? (R= 0.0821 L.ATM/mol.k)

User Richflow
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Final answer:

To find the volume of 64g of oxygen gas at 600 torr and 12 degrees C, convert pressure to atm, temperature to Kelvin, calculate moles of oxygen, and apply the Ideal Gas Law to solve for the volume.

Step-by-step explanation:

Calculating the Volume of Oxygen Gas

To determine the volume of 64g of oxygen gas at a pressure of 600 torr and a temperature of 12 degrees C, we can use the Ideal Gas Law, PV = nRT. First, convert the given pressure from torr to atm (1 atm = 760 torr), and the temperature to Kelvin (K = C + 273.15). After these conversions, we calculate the moles of oxygen gas using its molar mass (O2 = 32.00 g/mol). Then, we can plug these values into the Ideal Gas Law equation to solve for the volume V.

First, calculate the moles (n) of oxygen:
/n = 64g / 32.00 g/mol = 2 moles

Next, convert the pressure to atm and temperature to Kelvin:
P = 600 torr / 760 torr/atm = 0.7895 atmT = 12 C + 273.15 = 285.15 K

Now, use the Ideal Gas Law to find the volume:
V = nRT / PV = (2 moles) * (0.0821 L.atm/mol.K) * (285.15 K) / (0.7895 atm)

Perform the calculations to obtain the volume of oxygen gas at the given conditions.

User Misha Mashina
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