Final answer:
The F-Xe-F bond angles in XeF4 are 90 degrees adjacent to each other and 180 degrees across the molecular plane due to its square planar molecular structure.
Step-by-step explanation:
The F-Xe-F bond angles in XeF4 can be predicted using the electron-pair geometry and the molecular structure of the molecule. According to the data, XeF4 has six regions of high electron density surrounding the xenon atom, which are made up of two lone pairs and four bonding pairs. This arrangement leads to an octahedral electron-pair geometry. However, the molecular structure of XeF4 is square planar, as illustrated by Figure 4.25 and Figure 7.25 in the given references, with the lone pairs situated directly opposite each other. As a result, the F-Xe-F bond angles are 90 degrees between the fluorine atoms adjacent to each other and 180 degrees across the molecular plane.