Question

Write the singly bonded Lewis dot structure for SF6. Which of the following statements best describes this structure? a. It exceeds the octet rule b. It has less than an octet on at least one atom. c. It has a lone pair of electrons on the sulfur atom. d. It obeys the octet rule on all atoms. e. It has less than an octet of electrons on all atoms.

Answer 1

The Lewis dot structure for SF6 shows sulfur with 12 electrons, using sp3d2 hybridization to form an octahedral structure, which signifies that it exceeds the octet rule.

Step-by-step explanation:

When writing the singly bonded Lewis dot structure for SF6, you'll find that the sulfur atom is the central atom with six fluorine atoms bonded to it. Each of the six fluorine atoms will contribute one electron to the bond, and the sulfur atom will contribute one electron to each bond, resulting in sulfur having a total of 12 electrons around it, which is beyond the normal octet. This means that SF6 is an example of an expanded valence shell molecule where sulfur's d orbitals are used to accommodate additional electrons. Therefore, SF6 has an octahedral structure with sp3d2 hybridization, and the best description of this structure is that it exceeds the octet rule.