Question

This reaction takes place in base. Cancel the H₂Os on both sides to complete the redox reaction.

Cr₂O₇⁻² + 14H₂O + 3C₂O₄⁻² = 2Cr⁺³ + 7H₂O + 6CO₂ + 14OH⁻

Answer 1

To complete the redox reaction given, we cancel out the 7 H₂O molecules on each side of the equation, resulting in a balanced reaction of Cr₂O₇⁻² + 7H₂O + 3C₂O₄⁻² = 2Cr⁺³ + 6CO₂ + 14OH⁻ after the water molecules have been removed.

Step-by-step explanation:

The subject of this question is Chemistry, and it appears to be designed for a high school level based on the complexity of the redox reaction balancing in a basic solution. To complete the redox reaction, we need to cancel out common terms on both sides of the equation. Starting with the provided reaction:

Cr₂O₇⁻² + 14H₂O + 3C₂O₄⁻² = 2Cr⁺³ + 7H₂O + 6CO₂ + 14OH⁻

We can eliminate 7 H₂O molecules from each side:

Cr₂O₇⁻² + 7H₂O + 3C₂O₄⁻² = 2Cr⁺³ + 6CO₂ + 14OH⁻

This gives us the final balanced redox reaction in a basic solution:

Cr₂O₇⁻² + 7H₂O + 3C₂O₄⁻² → 2Cr⁺³ + 6CO₂ + 14OH⁻