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Write separate equations for the half reactions of this redox reaction:

Cr₂O₇⁻² (aq) + C₂O₄⁻² (aq) = Cr⁺³(aq) +CO₂ (g)
Carbon oxidized
Chromium reduced

User Afia
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1 Answer

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Final answer:

The half reactions of this redox reaction are as follows: oxidation - Cr₂O₇⁻² (aq) → 2Cr³+ (aq), reduction - C₂O₄⁻² (aq) → CO₂ (g), Chromium is being oxidized while carbon is being reduced.

Step-by-step explanation:

The half reactions for this redox reaction are as follows:



Oxidation half-reaction:

Cr₂O₇⁻² (aq) → 2Cr³+ (aq)



Reduction half-reaction:

C₂O₄⁻² (aq) → CO₂ (g)



In the oxidation half-reaction, the chromium ion (Cr) is being oxidized from a +2 oxidation state to a +3 state, while in the reduction half-reaction, the carbon ion (C) is being oxidized from a +3 oxidation state to produce carbon dioxide (CO₂).

User Cuonglm
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