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Consider the following electron configurations.

Element A: 1s22s1
Element B: 1s22s22p63s1
Element C: 1s22s22p63s23p64s1
Which of the following is the correct order for decreasing IE1 (i.e., largest to smallest)?

User Renefritze
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1 Answer

5 votes

Final answer:

The correct order for decreasing IE1 (largest to smallest) is Element C, Element B, Element A.

Step-by-step explanation:

The correct order for decreasing IE1 (largest to smallest) is Element C, Element B, Element A.

The first ionization energy generally increases across a period and decreases down a group on the periodic table. However, there are exceptions to this trend, such as in the case of Element C (Sulfur), where the repulsion between electrons in the same p orbital makes it easier to remove an electron. Element B (Nitrogen) has a higher ionization energy than Element A (Lithium) because it has a higher atomic number and therefore more protons, leading to a stronger attraction between the nucleus and the outermost electron.

User Chiurox
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