Question

After the following code executes, what is the output if user enters 0?

int x = -1;
cout << "Enter a 0 or 1: ";
cin >> x;
if (c)
cout << "true" << endl;
else
cout << "false" << endl;
a. nothing will be displayed
b. false
c. x
d. true
e. 0

Answer 1

The output, when the user enters 0, will be 'false' provided 'c' in the conditional statement is a typo and should actually be 'x'. If 'c' is not a typo, then the code snippet contains an error and would not compile.

Step-by-step explanation:

When the following code executes and the user enters 0, there appears to be a mistake in the provided code snippet because the variable 'c' is used in the conditional statement without being defined or assigned any value previously. Assuming that 'c' was meant to be 'x', the output would be:

false

This is because in C++, a numerical value of 0 is considered as false and any non-zero value is considered as true. The code checks the value of 'x', which the user sets to 0, and evaluates the 'if' condition, which becomes false. Consequently, the 'else' part of the 'if-else' statement is executed, printing 'false' to the output.