Final answer:
To calculate the volume occupied by 3.40 g of NH3 at STP, divide the mass by the molar mass to find the number of moles, then use the ideal gas law equation. Substituting the values into the equation gives a volume of 4.84 L.
Step-by-step explanation:
To calculate the volume occupied by 3.40 g of NH3 at STP, we can use the ideal gas law equation: V = (nRT) / P, where n is the number of moles, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure.
Under STP conditions, 1 mole of any gas occupies 22.4 L. we first need to calculate the number of moles by dividing the mass by the molar mass of NH3. The molar mass of NH3 is 17 g/mol, so we have:
n = (3.40 g) / (17 g/mol) = 0.20 moles
Substituting the values into the equation, we get:
V = (0.20 mol x 0.08206 L atm/K mol x 273 K) / 1 atm
Simplifying the calculation:
V = 4.84 L