Final answer:
The force required to stop a 40 kg person running at 12 m/s over 14 seconds is calculated using Newton's second law, resulting in a force of 34.28 Newtons.
Step-by-step explanation:
To calculate the force required to stop a 40 kg person running at a velocity of 12 m/s over a time interval of 14 seconds, we use the formula F = ma, where F is the force, m is the mass of the object, and a is the acceleration.
First, we need to determine the acceleration using the formula a = ∆v / t, where ∆v is the change in velocity and t is the time taken to stop.
The change in velocity is 12 m/s (from 12 m/s to 0 m/s), and the time is 14 seconds.
Acceleration a = ∆v / t
= 12 m/s / 14 s
= 0.857 m/s2.
Now, we can calculate the force: F = ma = 40 kg * 0.857 m/s2
= 34.28 N.
The force exerted to bring the person to a stop is 34.28 Newtons.