Answer:
B
Explanation:
Alright, to start off... we need to find a range of value that sqr 74 is between.
To do that, we can check by just trying some random numbers.
Let's try 8 -- 8^2 is 64. Let's try 9 -- 9^2 is 81. So the sqr 64 is 8 and sqr 81 is 9.
sqr 74 is between sqr 64 and sqr 81, so the statement is true. However, the multiple-choice has decimal numbers, meaning that they want us to be more specific.
First, we can cross out 9.5, because we don't want to expand our range, we want to keep it as accurate as possible.
That leaves us 8.5
To find if 8.5 fits the criteria, meaning that it can't be larger than sqr 74, we can use two methods.
The first method is preferred, you simply need to multiply them. I hope you know how to do that by hand. We get 72.25
The second method is less preferred but works. We need to approximate the value by finding the mean of 64 and 81, because 8.5 is the mean of 8 and 9. The approximate value should be very close to the true value. By doing (81+64)/2, we get 72.5
Now, double-check: is the 74 between 72.25 and 81? Yes, it is!
Hence, that gives us the answer that sqr74 is between 8.5 (sqr 72.25) and 9 (sqr 81)